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(y^2+2.4y+1.44)=0
We get rid of parentheses
y^2+2.4y+1.44=0
a = 1; b = 2.4; c = +1.44;
Δ = b2-4ac
Δ = 2.42-4·1·1.44
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$y=\frac{-b}{2a}=\frac{-2.4}{2}=-1+0.4/2$
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